x^2+14^2=29^2

Solution for x^2+14^2=29^2 equation:

x^2+14^2=29^2

We move all terms to the left:

x^2+14^2-(29^2)=0

We add all the numbers together, and all the variables

x^2-645=0

a = 1; b = 0; c = -645;
Δ = b2-4ac
Δ = 02-4·1·(-645)
Δ = 2580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2580}=\sqrt{4*645}=\sqrt{4}*\sqrt{645}=2\sqrt{645}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{645}}{2*1}=\frac{0-2\sqrt{645}}{2}
=-\frac{2\sqrt{645}}{2}
=-\sqrt{645}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{645}}{2*1}=\frac{0+2\sqrt{645}}{2}
=\frac{2\sqrt{645}}{2}
=\sqrt{645}
$